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This topic is now archived and is closed to further replies. # [Video] Hand Stall Tutorial

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Name: Hand Stall Tutorial

Category: Beginner Freehand Tutorials

Date Added: 07 May 2011 - 04:18 PM

Submitter: Ph0toN

Short Description: None Provided

By L3th4lity. Here is the very basic freehand hand stall. For more tutorials and such like these please visit glowsticking.com The stall explained by Spazzman the most fundmental point of any stall-like move : momentum. What exactly is momentum? Before we answer that, will will make the assumption that in order to execute a handstall (or any stall) you have to equal the momentum of the glowstick and the hand. If you have taken a high school physics course, or have a minimal understanding of the scientific world, then you can comprehend momentum in the following simplified formula: p = mv Where p = Momentum m = Mass v = Velocity So, we can quickly conclude that the momentum of the glowstick is its mass multiplied by velocity, or, speed. Now, there is one more piece of information you should be aware of before we move on; 1. The total momentum of any group of objects remains the same unless outside forces act on the objects (in other words, the law of conservation of momentum) Now that you are informed about the relevent properties of momentum, we can proceed to the next formula; knowing that the total momentum in a system will not change, you can see: deltaP = (-)deltaP In words: the change in momentum of one object must be opposite and equal to the change in momentum of the other object. Lets put this closed collision system in terms of glowsticking, more specifically handstalls. There are two objects, your hand and the glowstick. Now, the total momentum of this interaction will not change, but the individual momentum between your hand and the stick will change. Well, with a few more equations we can derive the formula for a handstall, in essence, you will never drop a handstall again if the formula is calculated correctly. m1u1 + m2u2 = m1v1 + m2v2 Where u = velocity before the collision v = velocity after the collision 1/2 = denote object 1/2 respectively So, what does this all mean? The mass of both objects (hand and glowstick) are now considered constants in this system since those values will not be changing. IN CONCLUSION, this shows that in order to execute a handstall, the velocity of the second object MUST EQUAL the velocity of the first object. "But spazz, I don't want to read this long ass post, I don't come to gsc to do physics homework" "its ok, all you really need to know is, lower your hand at the same speed of the stick, the stick will stall, for beginners this downward movement is very big, over time you can make the movement smaller and smaller until its almost unseen by anyone watching."

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